What are the solutions to the equation x^2+8=0 ?

The solutions to the equation x^2+8=0 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of x^2+8=0

The zeros of x^2+8=0 are x=2sqrt(2)i,x=-2sqrt(2)i

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x^{2} + 8 = 0

x = 22 i, x = - 22 i

Solution steps

x^{2} + 8 = 0

Move

8

to the right side

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

3.1 x + 6.2 = 1.05 x^{2}

(2 x - 1) (3 x + 5) = (x + 2) (2 x - 1)

(256 x^{16})^{\frac{1}{4}}

- 11 \cdot - 7

\frac{1}{3} (6)^{3}

What are the solutions to the equation x^2+8=0 ?
The solutions to the equation x^2+8=0 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of x^2+8=0
The zeros of x^2+8=0 are x=2sqrt(2)i,x=-2sqrt(2)i