What is the answer to |2x^2-x-1|=3 ?

The answer to |2x^2-x-1|=3 is x=(1-sqrt(33))/4 \lor x=(1+sqrt(33))/4

Solve for x: |2x^2-x-1|=3

The solution is x=(1-sqrt(33))/4 \lor x=(1+sqrt(33))/4

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2 x^{2} - x - 1 = 3

x = \frac{1 - 33}{4} or x = \frac{1 + 33}{4}

Decimal Notation

x = - 1.18614 \dots, x = 1.68614 \dots

Solution steps

2 x^{2} - x - 1 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x^{2} - x - 1 = - 3 or 2 x^{2} - x - 1 = 3

2 x^{2} - x - 1 = - 3 or 2 x^{2} - x - 1 = 3

No Solution or (x = \frac{1 - 33}{4} or x = \frac{1 + 33}{4})

x = \frac{1 - 33}{4} or x = \frac{1 + 33}{4}

- 14 - 11 ∣ - 9 + 6 x ∣ = - 13

x^{2} - 5 ∣ x ∣ - 6 = 0

x, y = f ∣ x ∣

∣ 5 - x ∣ = 12

- 4 ∣ q ∣ = - 9

What is the answer to |2x^2-x-1|=3 ?
The answer to |2x^2-x-1|=3 is x=(1-sqrt(33))/4 \lor x=(1+sqrt(33))/4
Solve for x: |2x^2-x-1|=3
The solution is x=(1-sqrt(33))/4 \lor x=(1+sqrt(33))/4