What is the answer to |2x^2-x-8|=7 ?

The answer to |2x^2-x-8|=7 is x=-5/2 \lor x=-1/2 \lor x=1\lor x=3

Solve for x: |2x^2-x-8|=7

The solution is x=-5/2 \lor x=-1/2 \lor x=1\lor x=3

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2 x^{2} - x - 8 = 7

x = - \frac{5}{2} or x = - \frac{1}{2} or x = 1 or x = 3

Solution steps

2 x^{2} - x - 8 = 7

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x^{2} - x - 8 = - 7 or 2 x^{2} - x - 8 = 7

2 x^{2} - x - 8 = - 7 or 2 x^{2} - x - 8 = 7

(x = - \frac{1}{2} or x = 1) or (x = - \frac{5}{2} or x = 3)

x = - \frac{5}{2} or x = - \frac{1}{2} or x = 1 or x = 3

15 = 3 - ∣ x + 8 ∣

2 ∣ x + 2 ∣ + 1 = 9

∣ x ∣ = 59.9

∣ 4 p - 5 ∣ = 0

∣ 2 x + 5 ∣ = x

What is the answer to |2x^2-x-8|=7 ?
The answer to |2x^2-x-8|=7 is x=-5/2 \lor x=-1/2 \lor x=1\lor x=3
Solve for x: |2x^2-x-8|=7
The solution is x=-5/2 \lor x=-1/2 \lor x=1\lor x=3