What is the answer to 1=|x^2-2| ?

The answer to 1=|x^2-2| is x=-sqrt(3)\lor x=-1\lor x=1\lor x=sqrt(3)

Solve for x: 1=|x^2-2|

The solution is x=-sqrt(3)\lor x=-1\lor x=1\lor x=sqrt(3)

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1 = x^{2} - 2

x = - 3 or x = - 1 or x = 1 or x = 3

Solution steps

1 = x^{2} - 2

Switch sides

x^{2} - 2 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 = - 1 or x^{2} - 2 = 1

x^{2} - 2 = - 1 or x^{2} - 2 = 1

(x = - 1 or x = 1) or (x = - 3 or x = 3)

x = - 3 or x = - 1 or x = 1 or x = 3

∣ 12 - 4 c ∣ = 15

3 - 2 ∣ 2 j - 5 ∣ = - 4

∣ x - 3 ∣ + 2 = 18

∣ k ∣ - 7 = - 7

∣ 2 x + 8 ∣ = 0

What is the answer to 1=|x^2-2| ?
The answer to 1=|x^2-2| is x=-sqrt(3)\lor x=-1\lor x=1\lor x=sqrt(3)
Solve for x: 1=|x^2-2|
The solution is x=-sqrt(3)\lor x=-1\lor x=1\lor x=sqrt(3)