What is the answer to x^2+2x-10=|x+2|+6 ?

The answer to x^2+2x-10=|x+2|+6 is x=(-3-sqrt(65))/2 \lor x=(-1+sqrt(73))/2

Solve for x: x^2+2x-10=|x+2|+6

The solution is x=(-3-sqrt(65))/2 \lor x=(-1+sqrt(73))/2

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x^{2} + 2 x - 10 = ∣ x + 2 ∣ + 6

x = \frac{- 3 - 65}{2} or x = \frac{- 1 + 73}{2}

Solution steps

x^{2} + 2 x - 10 = ∣ x + 2 ∣ + 6

Find positive and negative intervals

x < - 2, x \geq - 2

Solve the inequality for each interval

x = \frac{- 3 - 65}{2} or x = \frac{- 1 + 73}{2}

∣ r - 80 ∣ = 1

∣ z ∣ = a

∣ z + 3 ∣ = 5

∣ x ∣ + 6 = - 4

∣ 3 x + 15 ∣ = 3

What is the answer to x^2+2x-10=|x+2|+6 ?
The answer to x^2+2x-10=|x+2|+6 is x=(-3-sqrt(65))/2 \lor x=(-1+sqrt(73))/2
Solve for x: x^2+2x-10=|x+2|+6
The solution is x=(-3-sqrt(65))/2 \lor x=(-1+sqrt(73))/2