What are the solutions to the equation 3^2+x^2=4^2 ?

The solutions to the equation 3^2+x^2=4^2 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 3^2+x^2=4^2

The zeros of 3^2+x^2=4^2 are x=sqrt(7),x=-sqrt(7)

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3^{2} + x^{2} = 4^{2}

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

3^{2} + x^{2} = 4^{2}

Move

3^{2}

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

2 x - 6 = x + 6

53

5.4 = 0.3 (x + 8)

3 x^{2} + 14 x - 49

3 x^{2} - 7 x + 6 = 0

What are the solutions to the equation 3^2+x^2=4^2 ?
The solutions to the equation 3^2+x^2=4^2 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 3^2+x^2=4^2
The zeros of 3^2+x^2=4^2 are x=sqrt(7),x=-sqrt(7)