What is the answer to x^2+8x+4=|x+2|+3 ?

The answer to x^2+8x+4=|x+2|+3 is x=(-9-sqrt(69))/2 \lor x=(-7+sqrt(53))/2

Solve for x: x^2+8x+4=|x+2|+3

The solution is x=(-9-sqrt(69))/2 \lor x=(-7+sqrt(53))/2

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x^{2} + 8 x + 4 = ∣ x + 2 ∣ + 3

x = \frac{- 9 - 69}{2} or x = \frac{- 7 + 53}{2}

Decimal Notation

x = - 8.65331 \dots, x = 0.14005 \dots

Solution steps

x^{2} + 8 x + 4 = ∣ x + 2 ∣ + 3

Find positive and negative intervals

x < - 2, x \geq - 2

Solve the inequality for each interval

x = \frac{- 9 - 69}{2} or x = \frac{- 7 + 53}{2}

∣ 8 - 2 x ∣ = 0

∣ - 3 x + 3 ∣ = 33

∣ - x ∣ + 9 = 12

- ∣ 3 x - 4 ∣ - 12 = 10

0 = ∣ x - 1 ∣ - 3

What is the answer to x^2+8x+4=|x+2|+3 ?
The answer to x^2+8x+4=|x+2|+3 is x=(-9-sqrt(69))/2 \lor x=(-7+sqrt(53))/2
Solve for x: x^2+8x+4=|x+2|+3
The solution is x=(-9-sqrt(69))/2 \lor x=(-7+sqrt(53))/2