What is the answer to |4-2t|+5=12 ?

The answer to |4-2t|+5=12 is t=-3/2 \lor t= 11/2

Solve for t: |4-2t|+5=12

The solution is t=-3/2 \lor t= 11/2

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∣ 4 - 2 t ∣ + 5 = 12

t = - \frac{3}{2} or t = \frac{11}{2}

Solution steps

∣ 4 - 2 t ∣ + 5 = 12

Move

5

to the right side

∣ 4 - 2 t ∣ = 7

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

4 - 2 t = - 7 or 4 - 2 t = 7

4 - 2 t = - 7 or 4 - 2 t = 7

t = - \frac{3}{2} or t = \frac{11}{2}

∣ v + 2 ∣ = 1

4 ∣ 9 n - 8 ∣ - 9 = - 5

3 ∣ 3 x - 8 ∣ = 30

∣ 2 - 2 t ∣ + 5 = 15

4 ∣ 3 b - 1 ∣ = 28

What is the answer to |4-2t|+5=12 ?
The answer to |4-2t|+5=12 is t=-3/2 \lor t= 11/2
Solve for t: |4-2t|+5=12
The solution is t=-3/2 \lor t= 11/2