What are the solutions to the equation (2b-20)^2=12 ?

The solutions to the equation (2b-20)^2=12 are b=sqrt(3)+10,b=-sqrt(3)+10

Find the zeros of (2b-20)^2=12

The zeros of (2b-20)^2=12 are b=sqrt(3)+10,b=-sqrt(3)+10

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(2 b - 20)^{2} = 12

b = 3 + 10, b = - 3 + 10

Decimal

b = 11.73205 \dots, b = 8.26794 \dots

Solution steps

(2 b - 20)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 b - 20 = 12 : b = 3 + 10

Solve

2 b - 20 = - 12 : b = - 3 + 10

The solutions to the quadratic equation are:

b = 3 + 10, b = - 3 + 10

\frac{x}{6} = - 1

- 1 \cdot 3

- 5 y - 9 = - (y - 1)

∣ x + 7 ∣ \leq 2

4 d - 7 = 21

What are the solutions to the equation (2b-20)^2=12 ?
The solutions to the equation (2b-20)^2=12 are b=sqrt(3)+10,b=-sqrt(3)+10
Find the zeros of (2b-20)^2=12
The zeros of (2b-20)^2=12 are b=sqrt(3)+10,b=-sqrt(3)+10