What is the answer to 2|2[3(x+1)-3]|+1=13 ?

The answer to 2|2[3(x+1)-3]|+1=13 is x=-1\lor x=1

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2|2[3(x+1)-3]|+1=13

2 ∣ 2 [3 (x + 1) - 3] ∣ + 1 = 13

x = - 1 or x = 1

Solution steps

2 ∣ 2 [3 (x + 1) - 3] ∣ + 1 = 13

Move

1

to the right side

2 ∣ 2 [3 (x + 1) - 3] ∣ = 12

Divide both sides by

2

∣ 2 [3 (x + 1) - 3] ∣ = 6

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 [3 (x + 1) - 3] = - 6 or 2 [3 (x + 1) - 3] = 6

2 [3 (x + 1) - 3] = - 6 or 2 [3 (x + 1) - 3] = 6

x = - 1 or x = 1

2 y + 6 = - ∣ y + 4 ∣

∣ 5 x + 3 ∣ + 2 = 9

x^{2} - 5 x + 3 = 0

∣ x + 3 ∣ + 2 = 2 x + 8

\frac{2 x - 5}{3} = 11

What is the answer to 2|2[3(x+1)-3]|+1=13 ?
The answer to 2|2[3(x+1)-3]|+1=13 is x=-1\lor x=1
Solve for x: 2|2[3(x+1)-3]|+1=13
The solution is x=-1\lor x=1