What is the answer to 5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0 ?

The answer to 5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0 is x=-9/17

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5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0

5 (x - 2)^{2} - 5 (x + 3)^{2} + (2 x - 1) (5 x + 2) - 10 x^{2} = 0

x = - \frac{9}{17}

Decimal Notation

x = - 0.52941 \dots

Solution steps

5 (x - 2)^{2} - 5 (x + 3)^{2} + (2 x - 1) (5 x + 2) - 10 x^{2} = 0

Expand

5 (x - 2)^{2} - 5 (x + 3)^{2} + (2 x - 1) (5 x + 2) - 10 x^{2} : - 51 x - 27

- 51 x - 27 = 0

Move

27

to the right side

- 51 x = 27

Divide both sides by

- 51

x = - \frac{9}{17}

4 x - 8 = 2 x

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\frac{1}{2} (4)^{- \frac{1}{2}}

∣ 8 y - 5 ∣ \geq 12

5 x + 6 < 19

What is the answer to 5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0 ?
The answer to 5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0 is x=-9/17
Solve for x: 5(x-2)^2-5(x+3)^2+(2x-1)(5x+2)-10x^2=0
The solution is x=-9/17