What is the answer to |x^2+10x|=25 ?

The answer to |x^2+10x|=25 is x=-5(1+sqrt(2))\lor x=-5\lor x=5(sqrt(2)-1)

Solve for x: |x^2+10x|=25

The solution is x=-5(1+sqrt(2))\lor x=-5\lor x=5(sqrt(2)-1)

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x^{2} + 10 x = 25

x = - 5 (1 + 2) or x = - 5 or x = 5 (2 - 1)

Decimal Notation

x = - 12.07106 \dots, x = - 5, x = 2.07106 \dots

Solution steps

x^{2} + 10 x = 25

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 10 x = - 25 or x^{2} + 10 x = 25

x^{2} + 10 x = - 25 or x^{2} + 10 x = 25

x = - 5 or (x = - 5 (1 + 2) or x = 5 (2 - 1))

x = - 5 (1 + 2) or x = - 5 or x = 5 (2 - 1)

∣ x ∣ + 14 = 23

\frac{∣ 5 + 9 x ∣}{10} = 5

x^{2} - 6 = 6 + x

∣ 2 x + 5 ∣ - 7 = 4

- 8 ∣ a - 9 ∣ - 10 = - 114

What is the answer to |x^2+10x|=25 ?
The answer to |x^2+10x|=25 is x=-5(1+sqrt(2))\lor x=-5\lor x=5(sqrt(2)-1)
Solve for x: |x^2+10x|=25
The solution is x=-5(1+sqrt(2))\lor x=-5\lor x=5(sqrt(2)-1)