What is the answer to sqrt(x^2+1)=|2x| ?

The answer to sqrt(x^2+1)=|2x| is x=-1/(sqrt(3))\lor x= 1/(sqrt(3))

Solve for x: sqrt(x^2+1)=|2x|

The solution is x=-1/(sqrt(3))\lor x= 1/(sqrt(3))

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x^{2} + 1 = ∣ 2 x ∣

x = - \frac{1}{3} or x = \frac{1}{3}

Decimal Notation

x = - 0.57735 \dots, x = 0.57735 \dots

Solution steps

x^{2} + 1 = ∣ 2 x ∣

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = - \frac{1}{3} or x = \frac{1}{3}

0 = - 9 ∣ y ∣

∣ 23 - 2 x ∣ = 0

- ∣ x - 5 ∣ - 2 = - 3

5 ∣ x - 6 ∣ = 8

x + 5 ∣ x + 8 ∣ = 4

What is the answer to sqrt(x^2+1)=|2x| ?
The answer to sqrt(x^2+1)=|2x| is x=-1/(sqrt(3))\lor x= 1/(sqrt(3))
Solve for x: sqrt(x^2+1)=|2x|
The solution is x=-1/(sqrt(3))\lor x= 1/(sqrt(3))