What is the answer to (x)=|x^2+3x-1| ?

The answer to (x)=|x^2+3x-1| is x=sqrt(5)-2\lor x=-1+sqrt(2)

Solve for x: (x)=|x^2+3x-1|

The solution is x=sqrt(5)-2\lor x=-1+sqrt(2)

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(x) = x^{2} + 3 x - 1

x = 5 - 2 or x = - 1 + 2

Decimal Notation

x = 0.23606 \dots, x = 0.41421 \dots

Solution steps

x = x^{2} + 3 x - 1

Find positive and negative intervals

x \leq \frac{- 13 - 3}{2}, \frac{- 13 - 3}{2} < x < \frac{13 - 3}{2}, x \geq \frac{13 - 3}{2}

Solve the inequality for each interval

No Solution or x = 5 - 2 or x = - 1 + 2

x = 5 - 2 or x = - 1 + 2

∣ 6 z + 5 ∣ - 16 = 0

∣ u - 4 ∣ = - \frac{1}{8}

∣ y + 3 ∣ = 4

∣ 2 + 2 y ∣ + 1 = 3

∣ y + 3 ∣ = 0

What is the answer to (x)=|x^2+3x-1| ?
The answer to (x)=|x^2+3x-1| is x=sqrt(5)-2\lor x=-1+sqrt(2)
Solve for x: (x)=|x^2+3x-1|
The solution is x=sqrt(5)-2\lor x=-1+sqrt(2)