What is the answer to |x+pi|=x^2+1 ?

The answer to |x+pi|=x^2+1 is x=(1-sqrt(4pi-3))/2 \lor x=(1+sqrt(4pi-3))/2

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|x+pi|=x^2+1

∣ x + π ∣ = x^{2} + 1

x = \frac{1 - 4 π - 3}{2} or x = \frac{1 + 4 π - 3}{2}

Decimal Notation

x = - 1.04647 \dots, x = 2.04647 \dots

Solution steps

∣ x + π ∣ = x^{2} + 1

Find positive and negative intervals

x < - π, x \geq - π

Solve the inequality for each interval

No Solution or (x = \frac{1 - 4 π - 3}{2} or x = \frac{1 + 4 π - 3}{2})

x = \frac{1 - 4 π - 3}{2} or x = \frac{1 + 4 π - 3}{2}

∣ 5 - 3 x ∣ + 2 = 19

∣ 6 p ∣ = 0

- 5 ∣ m + 1 ∣ + 8 = 3

∣ 3 p - 6 ∣ = 21

- 2 ∣ 2 x - 3 ∣ - 1 = - 11

What is the answer to |x+pi|=x^2+1 ?
The answer to |x+pi|=x^2+1 is x=(1-sqrt(4pi-3))/2 \lor x=(1+sqrt(4pi-3))/2