What is the answer to |x^2-8|=4 ?

The answer to |x^2-8|=4 is x=-2sqrt(3)\lor x=-2\lor x=2\lor x=2sqrt(3)

Solve for x: |x^2-8|=4

The solution is x=-2sqrt(3)\lor x=-2\lor x=2\lor x=2sqrt(3)

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x^{2} - 8 = 4

x = - 23 or x = - 2 or x = 2 or x = 23

Decimal Notation

x = - 3.46410 \dots, x = - 2, x = 2, x = 3.46410 \dots

Solution steps

x^{2} - 8 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 8 = - 4 or x^{2} - 8 = 4

x^{2} - 8 = - 4 or x^{2} - 8 = 4

(x = - 2 or x = 2) or (x = - 23 or x = 23)

x = - 23 or x = - 2 or x = 2 or x = 23

2 ∣ 4 x - 3 ∣ - 8 = - 3

∣ x + 7 ∣ = 27

∣ 3 x + 1 ∣ = 6 x + 2

∣ x ∣ - x = 0

∣ x ∣ - x = 6

What is the answer to |x^2-8|=4 ?
The answer to |x^2-8|=4 is x=-2sqrt(3)\lor x=-2\lor x=2\lor x=2sqrt(3)
Solve for x: |x^2-8|=4
The solution is x=-2sqrt(3)\lor x=-2\lor x=2\lor x=2sqrt(3)