What is the answer to |x-2|-2+x^2+4x=0 ?

The answer to |x-2|-2+x^2+4x=0 is x=-3\lor x=0

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|x-2|-2+x^2+4x=0

∣ x - 2 ∣ - 2 + x^{2} + 4 x = 0

x = - 3 or x = 0

Solution steps

∣ x - 2 ∣ - 2 + x^{2} + 4 x = 0

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

(x = - 3 or x = 0) or No Solution

x = - 3 or x = 0

\frac{n}{8} - 1 = 0

∣ x - 2 ∣ - 1 = 2

∣ 2 + 3 n ∣ - 1 = 27

∣ x - 0 ∣ = 1

∣ 4 x - 7 ∣ + 9 = 3

What is the answer to |x-2|-2+x^2+4x=0 ?
The answer to |x-2|-2+x^2+4x=0 is x=-3\lor x=0
Solve for x: |x-2|-2+x^2+4x=0
The solution is x=-3\lor x=0