What are the solutions to the equation 7x^2+14x-6=0 ?

The solutions to the equation 7x^2+14x-6=0 are x=(-7+sqrt(91))/7 ,x=-(7+sqrt(91))/7

Find the zeros of 7x^2+14x-6=0

The zeros of 7x^2+14x-6=0 are x=(-7+sqrt(91))/7 ,x=-(7+sqrt(91))/7

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7 x^{2} + 14 x - 6 = 0

x = \frac{- 7 + 91}{7}, x = - \frac{7 + 91}{7}

Decimal Notation

x = 0.36277 \dots, x = - 2.36277 \dots

Solution steps

7 x^{2} + 14 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

1 4^{2} - 4 \cdot 7 (- 6) = 291

x_{1, 2} = \frac{- 14 \pm 2 91}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 14 + 2 91}{2 \cdot 7}, x_{2} = \frac{- 14 - 2 91}{2 \cdot 7}

x = \frac{- 14 + 2 91}{2 \cdot 7} : \frac{- 7 + 91}{7}

x = \frac{- 14 - 2 91}{2 \cdot 7} : - \frac{7 + 91}{7}

The solutions to the quadratic equation are:

x = \frac{- 7 + 91}{7}, x = - \frac{7 + 91}{7}

22 5^{\frac{1}{2}}

\frac{x + 2}{x - 4} \geq 3

1 + \frac{0.04}{12}

9 x^{2} + 5 x - 1 = 0

\frac{11}{30} - (\frac{8}{15})^{2}

What are the solutions to the equation 7x^2+14x-6=0 ?
The solutions to the equation 7x^2+14x-6=0 are x=(-7+sqrt(91))/7 ,x=-(7+sqrt(91))/7
Find the zeros of 7x^2+14x-6=0
The zeros of 7x^2+14x-6=0 are x=(-7+sqrt(91))/7 ,x=-(7+sqrt(91))/7