What are the solutions to the equation 3t^2-22t=16 ?

The solutions to the equation 3t^2-22t=16 are t=8,t=-2/3

Find the zeros of 3t^2-22t=16

The zeros of 3t^2-22t=16 are t=8,t=-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 t^{2} - 22 t = 16

t = 8, t = - \frac{2}{3}

Decimal Notation

t = 8, t = - 0.66666 \dots

Solution steps

3 t^{2} - 22 t = 16

Move

16

to the left side

3 t^{2} - 22 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 (- 16) = 26

t_{1, 2} = \frac{- ( - 22 ) \pm 26}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 22 ) + 26}{2 \cdot 3}, t_{2} = \frac{- ( - 22 ) - 26}{2 \cdot 3}

t = \frac{- ( - 22 ) + 26}{2 \cdot 3} : 8

t = \frac{- ( - 22 ) - 26}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

t = 8, t = - \frac{2}{3}

3700

3 x^{2} + 24 x + 21

\frac{6 p + 4}{6} = \frac{4 p - 8}{3}

\frac{1}{5 !}

16 x^{4} - 25

What are the solutions to the equation 3t^2-22t=16 ?
The solutions to the equation 3t^2-22t=16 are t=8,t=-2/3
Find the zeros of 3t^2-22t=16
The zeros of 3t^2-22t=16 are t=8,t=-2/3