What is (x+6)/(x^2-8x+15)<= 0 ?

The solution to (x+6)/(x^2-8x+15)<= 0 is x<=-6\lor 3<x<5

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(x+6)/(x^2-8x+15)<= 0

\frac{x + 6}{x ^{2} - 8 x + 15} \leq 0

x \leq - 6 or 3 < x < 5

Interval Notation

(- \infty, - 6] \cup (3, 5)

Solution steps

\frac{x + 6}{x ^{2} - 8 x + 15} \leq 0

Factor

\frac{x + 6}{x ^{2} - 8 x + 15} : \frac{x + 6}{( x - 3 ) ( x - 5 )}

\frac{x + 6}{( x - 3 ) ( x - 5 )} \leq 0

Identify the intervals

x \leq - 6 or 3 < x < 5

x^{3} + x^{2} y + x y^{2} + y^{3}

(x + 1)^{2} + 4 = 14

- \frac{1}{6} (2 u - 5) = 4 (- 2 u + 5)

x^{2} - 21 x + 90

\frac{3 ^{8}}{3 ^{6}}

What is (x+6)/(x^2-8x+15)<= 0 ?
The solution to (x+6)/(x^2-8x+15)<= 0 is x<=-6\lor 3<x<5