What is the answer to |x^2-4x+4|=2 ?

The answer to |x^2-4x+4|=2 is x=2-sqrt(2)\lor x=2+sqrt(2)

Solve for x: |x^2-4x+4|=2

The solution is x=2-sqrt(2)\lor x=2+sqrt(2)

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x^{2} - 4 x + 4 = 2

x = 2 - 2 or x = 2 + 2

Decimal Notation

x = 0.58578 \dots, x = 3.41421 \dots

Solution steps

x^{2} - 4 x + 4 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x + 4 = - 2 or x^{2} - 4 x + 4 = 2

x^{2} - 4 x + 4 = - 2 or x^{2} - 4 x + 4 = 2

No Solution or (x = 2 - 2 or x = 2 + 2)

x = 2 - 2 or x = 2 + 2

3 x \frac{3}{2} = 6

∣ x + 3 ∣ = 4 - 5 x

∣ 9 x ∣ = 81

∣ 9 - 10 n ∣ = 61

3 ∣ x + 6 ∣ = 36

What is the answer to |x^2-4x+4|=2 ?
The answer to |x^2-4x+4|=2 is x=2-sqrt(2)\lor x=2+sqrt(2)
Solve for x: |x^2-4x+4|=2
The solution is x=2-sqrt(2)\lor x=2+sqrt(2)