What is the answer to |x^2+6x|=3x+1 ?

The answer to |x^2+6x|=3x+1 is x=-(9-sqrt(77))/2 \lor x=(-3+sqrt(13))/2

Solve for x: |x^2+6x|=3x+1

The solution is x=-(9-sqrt(77))/2 \lor x=(-3+sqrt(13))/2

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x^{2} + 6 x = 3 x + 1

x = - \frac{9 - 77}{2} or x = \frac{- 3 + 13}{2}

Decimal Notation

x = - 0.11251 \dots, x = 0.30277 \dots

Solution steps

x^{2} + 6 x = 3 x + 1

Find positive and negative intervals

x \leq - 6, - 6 < x < 0, x \geq 0

Solve the inequality for each interval

No Solution or x = - \frac{9 - 77}{2} or x = \frac{- 3 + 13}{2}

x = - \frac{9 - 77}{2} or x = \frac{- 3 + 13}{2}

1 + \frac{n}{6} = 2

∣ 15 - 2 k ∣ = 45

∣ 5 x - 8 ∣ = 27

∣ 3 a + 4 ∣ = 4 a - 10

0 = ∣ x + 1 ∣ - 3

What is the answer to |x^2+6x|=3x+1 ?
The answer to |x^2+6x|=3x+1 is x=-(9-sqrt(77))/2 \lor x=(-3+sqrt(13))/2
Solve for x: |x^2+6x|=3x+1
The solution is x=-(9-sqrt(77))/2 \lor x=(-3+sqrt(13))/2