What is the answer to |x^2-3|=2x+1 ?

The answer to |x^2-3|=2x+1 is x=sqrt(3)-1\lor x=1+sqrt(5)

Solve for x: |x^2-3|=2x+1

The solution is x=sqrt(3)-1\lor x=1+sqrt(5)

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x^{2} - 3 = 2 x + 1

x = 3 - 1 or x = 1 + 5

Decimal

x = 0.73205 \dots, x = 3.23606 \dots

Solution steps

x^{2} - 3 = 2 x + 1

Find positive and negative intervals

x \leq - 3, - 3 < x < 3, x \geq 3

Solve the inequality for each interval

No Solution or x = 3 - 1 or x = 1 + 5

x = 3 - 1 or x = 1 + 5

∣ 7 m + 3 ∣ + 6 = - 75

- 3.4 ∣ n + 1.6 ∣ = - 2.38

∣ 7 - 3 x ∣ = 5

∣ 2 x + 7 ∣ - 5 = 0

∣ 2 x + 7 ∣ - 5 = 7

What is the answer to |x^2-3|=2x+1 ?
The answer to |x^2-3|=2x+1 is x=sqrt(3)-1\lor x=1+sqrt(5)
Solve for x: |x^2-3|=2x+1
The solution is x=sqrt(3)-1\lor x=1+sqrt(5)