What is the answer to |x^2-3x+1|=1 ?

The answer to |x^2-3x+1|=1 is x=0\lor x=1\lor x=2\lor x=3

Solve for x: |x^2-3x+1|=1

The solution is x=0\lor x=1\lor x=2\lor x=3

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x^{2} - 3 x + 1 = 1

x = 0 or x = 1 or x = 2 or x = 3

Solution steps

x^{2} - 3 x + 1 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 3 x + 1 = - 1 or x^{2} - 3 x + 1 = 1

x^{2} - 3 x + 1 = - 1 or x^{2} - 3 x + 1 = 1

(x = 1 or x = 2) or (x = 0 or x = 3)

x = 0 or x = 1 or x = 2 or x = 3

∣ 9 q - 5 ∣ = 2 q

∣ - 3 y + 6 ∣ + 5 = 4

∣ x + 1 ∣ + 8 = 10

∣ - 5 + x ∣ = 3

∣ x ∣ - 8 = - 5

What is the answer to |x^2-3x+1|=1 ?
The answer to |x^2-3x+1|=1 is x=0\lor x=1\lor x=2\lor x=3
Solve for x: |x^2-3x+1|=1
The solution is x=0\lor x=1\lor x=2\lor x=3