What are the solutions to the equation 3x^2+17x-20=0 ?

The solutions to the equation 3x^2+17x-20=0 are x=1,x=-20/3

Find the zeros of 3x^2+17x-20=0

The zeros of 3x^2+17x-20=0 are x=1,x=-20/3

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3 x^{2} + 17 x - 20 = 0

x = 1, x = - \frac{20}{3}

Decimal Notation

x = 1, x = - 6.66666 \dots

Solution steps

3 x^{2} + 17 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 (- 20) = 23

x_{1, 2} = \frac{- 17 \pm 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 23}{2 \cdot 3}, x_{2} = \frac{- 17 - 23}{2 \cdot 3}

x = \frac{- 17 + 23}{2 \cdot 3} : 1

x = \frac{- 17 - 23}{2 \cdot 3} : - \frac{20}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{20}{3}

\frac{4}{4} 5

\frac{1}{2} (a - 2) = \frac{2}{3} a - 6

9 x - 6 \geq 3

2^{\frac{1}{1}}

k^{2} - 36

What are the solutions to the equation 3x^2+17x-20=0 ?
The solutions to the equation 3x^2+17x-20=0 are x=1,x=-20/3
Find the zeros of 3x^2+17x-20=0
The zeros of 3x^2+17x-20=0 are x=1,x=-20/3