What are the solutions to the equation 2a^2-20a=-4 ?

The solutions to the equation 2a^2-20a=-4 are a=5+sqrt(23),a=5-sqrt(23)

Find the zeros of 2a^2-20a=-4

The zeros of 2a^2-20a=-4 are a=5+sqrt(23),a=5-sqrt(23)

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2 a^{2} - 20 a = - 4

a = 5 + 23, a = 5 - 23

Decimal Notation

a = 9.79583 \dots, a = 0.20416 \dots

Solution steps

2 a^{2} - 20 a = - 4

Move

4

to the left side

2 a^{2} - 20 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 20)^{2} - 4 \cdot 2 \cdot 4 = 423

a_{1, 2} = \frac{- ( - 20 ) \pm 4 23}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 20 ) + 4 23}{2 \cdot 2}, a_{2} = \frac{- ( - 20 ) - 4 23}{2 \cdot 2}

a = \frac{- ( - 20 ) + 4 23}{2 \cdot 2} : 5 + 23

a = \frac{- ( - 20 ) - 4 23}{2 \cdot 2} : 5 - 23

The solutions to the quadratic equation are:

a = 5 + 23, a = 5 - 23

2 y = \frac{\frac{4}{5}}{\frac{3}{5}}

x^{5} y^{4} + x y^{3}

∣ 3 u - 9 ∣ = 6

- 5 \leq 4 - 3 \frac{x}{2} < 1

3 \cdot 27

What are the solutions to the equation 2a^2-20a=-4 ?
The solutions to the equation 2a^2-20a=-4 are a=5+sqrt(23),a=5-sqrt(23)
Find the zeros of 2a^2-20a=-4
The zeros of 2a^2-20a=-4 are a=5+sqrt(23),a=5-sqrt(23)