What is the answer to |1-2x|=x^2 ?

The answer to |1-2x|=x^2 is x=-1-sqrt(2)\lor x=-1+sqrt(2)\lor x=1

Solve for x: |1-2x|=x^2

The solution is x=-1-sqrt(2)\lor x=-1+sqrt(2)\lor x=1

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∣ 1 - 2 x ∣ = x^{2}

x = - 1 - 2 or x = - 1 + 2 or x = 1

Decimal Notation

x = - 2.41421 \dots, x = 0.41421 \dots, x = 1

Solution steps

∣ 1 - 2 x ∣ = x^{2}

Find positive and negative intervals

x \leq \frac{1}{2}, x > \frac{1}{2}

Solve the inequality for each interval

(x = - 1 - 2 or x = - 1 + 2) or x = 1

x = - 1 - 2 or x = - 1 + 2 or x = 1

4 = ∣ w + 2 ∣

∣ 6 - 10 r ∣ = 0

5 - 8 ∣ - 2 n ∣ = 75

2 ∣ y + 4 ∣ = 2

∣ - 4 x - 8 ∣ = - 2 x + 20

What is the answer to |1-2x|=x^2 ?
The answer to |1-2x|=x^2 is x=-1-sqrt(2)\lor x=-1+sqrt(2)\lor x=1
Solve for x: |1-2x|=x^2
The solution is x=-1-sqrt(2)\lor x=-1+sqrt(2)\lor x=1