What is the answer to (|x|+3)^2+16x=0 ?

The answer to (|x|+3)^2+16x=0 is x=-9\lor x=-1

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(|x|+3)^2+16x=0

(∣ x ∣ + 3)^{2} + 16 x = 0

x = - 9 or x = - 1

Solution steps

(∣ x ∣ + 3)^{2} + 16 x = 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

(x = - 9 or x = - 1) or No Solution

x = - 9 or x = - 1

∣ 2 x + 4 ∣ = - x - 5

∣ 4 x - 2 ∣ = - 5

∣ - 2 m ∣ = 14

∣ s - 4 ∣ + 2 = 4

∣ 3 x + 4 ∣ - 6 = 7

What is the answer to (|x|+3)^2+16x=0 ?
The answer to (|x|+3)^2+16x=0 is x=-9\lor x=-1
Solve for x: (|x|+3)^2+16x=0
The solution is x=-9\lor x=-1