What is the answer to |5-x^2|=3-x ?

The answer to |5-x^2|=3-x is x=(-1-sqrt(33))/2 \lor x=-1\lor x=2\lor x=(-1+sqrt(33))/2

Solve for x: |5-x^2|=3-x

The solution is x=(-1-sqrt(33))/2 \lor x=-1\lor x=2\lor x=(-1+sqrt(33))/2

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5 - x^{2} = 3 - x

x = \frac{- 1 - 33}{2} or x = - 1 or x = 2 or x = \frac{- 1 + 33}{2}

Decimal Notation

x = - 3.37228 \dots, x = - 1, x = 2, x = 2.37228 \dots

Solution steps

5 - x^{2} = 3 - x

Find positive and negative intervals

x < - 5, - 5 \leq x \leq 5, x > 5

Solve the inequality for each interval

x = \frac{- 1 - 33}{2} or (x = - 1 or x = 2) or x = \frac{- 1 + 33}{2}

x = \frac{- 1 - 33}{2} or x = - 1 or x = 2 or x = \frac{- 1 + 33}{2}

- 6 = ∣ 3 x - 3 ∣

- 3 ∣ x - 5 ∣ + 4 = 13

∣ y ∣ = 16, x + y = 0

∣ x ∣ = \frac{1}{7}

∣ x ∣ - 7 = 1

What is the answer to |5-x^2|=3-x ?
The answer to |5-x^2|=3-x is x=(-1-sqrt(33))/2 \lor x=-1\lor x=2\lor x=(-1+sqrt(33))/2
Solve for x: |5-x^2|=3-x
The solution is x=(-1-sqrt(33))/2 \lor x=-1\lor x=2\lor x=(-1+sqrt(33))/2