What are the solutions to the equation 1-(3x-5)^2=-7 ?

The solutions to the equation 1-(3x-5)^2=-7 are x=(2sqrt(2)+5)/3 ,x=(-2sqrt(2)+5)/3

Find the zeros of 1-(3x-5)^2=-7

The zeros of 1-(3x-5)^2=-7 are x=(2sqrt(2)+5)/3 ,x=(-2sqrt(2)+5)/3

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1 - (3 x - 5)^{2} = - 7

x = \frac{2 2 + 5}{3}, x = \frac{- 2 2 + 5}{3}

Decimal Notation

x = 2.60947 \dots, x = 0.72385 \dots

Solution steps

1 - (3 x - 5)^{2} = - 7

Move

1

to the right side

- (3 x - 5)^{2} = - 8

Divide both sides by

- 1

(3 x - 5)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 5 = 8 : x = \frac{2 2 + 5}{3}

Solve

3 x - 5 = - 8 : x = \frac{- 2 2 + 5}{3}

The solutions to the quadratic equation are:

x = \frac{2 2 + 5}{3}, x = \frac{- 2 2 + 5}{3}

b^{2} = 100

2 = \frac{k}{14} + 1

e^{x^{2} - y^{2}}

t^{2} - 4 t + 4

x^{2} + 4 x y - 21 y^{2}

What are the solutions to the equation 1-(3x-5)^2=-7 ?
The solutions to the equation 1-(3x-5)^2=-7 are x=(2sqrt(2)+5)/3 ,x=(-2sqrt(2)+5)/3
Find the zeros of 1-(3x-5)^2=-7
The zeros of 1-(3x-5)^2=-7 are x=(2sqrt(2)+5)/3 ,x=(-2sqrt(2)+5)/3