What is (8/3)0.2804^3(1-0.2804)^5 ?

The solution to (8/3)0.2804^3(1-0.2804)^5 is (2.12696E15)/(1.875E17)

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simplify (8/3)0.2804^3(1-0.2804)^5

simplify

(\frac{8}{3}) 0.280 4^{3} (1 - 0.2804)^{5}

\frac{2.12696 E 15}{1.875 E 17}

Decimal Notation

0.01134 \dots

Solution steps

(\frac{8}{3}) \cdot 0.280 4^{3} (1 - 0.2804)^{5}

Apply rule:

(a) = a

(\frac{8}{3}) = \frac{8}{3}

= \frac{8}{3} \cdot 0.280 4^{3} (1 - 0.2804)^{5}

0.280 4^{3} = 0.02204 \dots

= \frac{8}{3} \cdot 0.02204 \dots (1 - 0.2804)^{5}

Subtract the numbers:

1 - 0.2804 = 0.7196

= \frac{8}{3} \cdot 0.02204 \dots \cdot 0.719 6^{5}

0.719 6^{5} = 0.19295 \dots

= \frac{8}{3} \cdot 0.02204 \dots \cdot 0.19295 \dots

Multiply the numbers:

0.02204 \dots \cdot 0.19295 \dots = 0.00425 \dots

= \frac{8}{3} \cdot 0.00425 \dots

0.00425 \dots = \frac{2.12696 E 15}{5.0 E 17}

= \frac{8}{3} \cdot \frac{2.12696 E 15}{5.0 E 17}

\frac{8}{3} \cdot \frac{2.12696 E 15}{5.0 E 17} = \frac{2.12696 E 15}{1.875 E 17}

= \frac{2.12696 E 15}{1.875 E 17}

(\frac{9}{2}) + (\frac{9}{4})

\frac{x}{6} = 12

(y^{2})^{\frac{1}{2}}

x^{2} - 10 x + 169 = 0

m^{2} - m > 0

What is (8/3)0.2804^3(1-0.2804)^5 ?
The solution to (8/3)0.2804^3(1-0.2804)^5 is (2.12696E15)/(1.875E17)