What is the answer to 7|4(x+3)(x+1)|-28=0 ?

The answer to 7|4(x+3)(x+1)|-28=0 is x=-2-sqrt(2)\lor x=-2\lor x=-2+sqrt(2)

Solve for x: 7|4(x+3)(x+1)|-28=0

The solution is x=-2-sqrt(2)\lor x=-2\lor x=-2+sqrt(2)

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7 ∣ 4 (x + 3) (x + 1) ∣ - 28 = 0

x = - 2 - 2 or x = - 2 or x = - 2 + 2

Decimal Notation

x = - 3.41421 \dots, x = - 2, x = - 0.58578 \dots

Solution steps

7 ∣ 4 (x + 3) (x + 1) ∣ - 28 = 0

Move

28

to the right side

7 ∣ 4 (x + 3) (x + 1) ∣ = 28

Divide both sides by

7

∣ 4 (x + 3) (x + 1) ∣ = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

4 (x + 3) (x + 1) = - 4 or 4 (x + 3) (x + 1) = 4

4 (x + 3) (x + 1) = - 4 or 4 (x + 3) (x + 1) = 4

x = - 2 or (x = - 2 - 2 or x = - 2 + 2)

x = - 2 - 2 or x = - 2 or x = - 2 + 2

8 = ∣ x - 2.5 ∣

5 + ∣ 10 m + 3 ∣ = 32

∣ x - 5 ∣ + 3 = 3

∣ 5 x + 3 ∣ - 7 = 4 x + 1

∣ 3 x + 1 ∣ + 5 = 4

What is the answer to 7|4(x+3)(x+1)|-28=0 ?
The answer to 7|4(x+3)(x+1)|-28=0 is x=-2-sqrt(2)\lor x=-2\lor x=-2+sqrt(2)
Solve for x: 7|4(x+3)(x+1)|-28=0
The solution is x=-2-sqrt(2)\lor x=-2\lor x=-2+sqrt(2)