What is the answer to |2x^2-3|-x=3 ?

The answer to |2x^2-3|-x=3 is x=-3/2 \lor x=-1/2 \lor x=0\lor x=2

Solve for x: |2x^2-3|-x=3

The solution is x=-3/2 \lor x=-1/2 \lor x=0\lor x=2

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2 x^{2} - 3 - x = 3

x = - \frac{3}{2} or x = - \frac{1}{2} or x = 0 or x = 2

Decimal Notation

x = - 1.5, x = - 0.5, x = 0, x = 2

Solution steps

2 x^{2} - 3 - x = 3

Find positive and negative intervals

x \leq - \frac{3}{2}, - \frac{3}{2} < x < \frac{3}{2}, x \geq \frac{3}{2}

Solve the inequality for each interval

x = - \frac{3}{2} or (x = - \frac{1}{2} or x = 0) or x = 2

x = - \frac{3}{2} or x = - \frac{1}{2} or x = 0 or x = 2

∣ x - 8 ∣ = 16

y, x + ∣ y ∣ = 2 y

∣ - 4 - 3 n ∣ 4 = 2

∣ 6 x + 5 ∣ = 3

∣ 4 p - 3 ∣ + 7 = 24

What is the answer to |2x^2-3|-x=3 ?
The answer to |2x^2-3|-x=3 is x=-3/2 \lor x=-1/2 \lor x=0\lor x=2
Solve for x: |2x^2-3|-x=3
The solution is x=-3/2 \lor x=-1/2 \lor x=0\lor x=2