What is the answer to |x^2-1|-x=0 ?

The answer to |x^2-1|-x=0 is x=(sqrt(5)-1)/2 \lor x=(1+sqrt(5))/2

Solve for x: |x^2-1|-x=0

The solution is x=(sqrt(5)-1)/2 \lor x=(1+sqrt(5))/2

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x^{2} - 1 - x = 0

x = \frac{5 - 1}{2} or x = \frac{1 + 5}{2}

Decimal Notation

x = 0.61803 \dots, x = 1.61803 \dots

Solution steps

x^{2} - 1 - x = 0

Find positive and negative intervals

x \leq - 1, - 1 < x < 1, x \geq 1

Solve the inequality for each interval

No Solution or x = \frac{5 - 1}{2} or x = \frac{1 + 5}{2}

x = \frac{5 - 1}{2} or x = \frac{1 + 5}{2}

- 4 ∣ y + 3 ∣ = - 36

∣ w ∣ = - 8

∣ w ∣ = - 6

x, ∣ x - 4 ∣ = 11

∣ x - 4 ∣ - x^{2} = - 3

What is the answer to |x^2-1|-x=0 ?
The answer to |x^2-1|-x=0 is x=(sqrt(5)-1)/2 \lor x=(1+sqrt(5))/2
Solve for x: |x^2-1|-x=0
The solution is x=(sqrt(5)-1)/2 \lor x=(1+sqrt(5))/2