What is the answer to x^2+3x-11=|x+4|+9 ?

The answer to x^2+3x-11=|x+4|+9 is x=-2(1+sqrt(5))\lor x=4

Solve for x: x^2+3x-11=|x+4|+9

The solution is x=-2(1+sqrt(5))\lor x=4

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x^{2} + 3 x - 11 = ∣ x + 4 ∣ + 9

x = - 2 (1 + 5) or x = 4

Decimal Notation

x = - 6.47213 \dots, x = 4

Solution steps

x^{2} + 3 x - 11 = ∣ x + 4 ∣ + 9

Find positive and negative intervals

x < - 4, x \geq - 4

Solve the inequality for each interval

x = - 2 (1 + 5) or x = 4

3 ∣ x - 5 ∣ = 7

3 ∣ x - 5 ∣ = 8

∣ 10 x + 3 ∣ + 9 = - 58

∣ 4 b + 3 ∣ = 15 - 2 b

∣ 6 u - 18 ∣ = 12

What is the answer to x^2+3x-11=|x+4|+9 ?
The answer to x^2+3x-11=|x+4|+9 is x=-2(1+sqrt(5))\lor x=4
Solve for x: x^2+3x-11=|x+4|+9
The solution is x=-2(1+sqrt(5))\lor x=4