What is the answer to |0.541x+7|=x^2-4 ?

The answer to |0.541x+7|=x^2-4 is x=(541-3sqrt(4921409))/(2000)\lor x=(541+3sqrt(4921409))/(2000)

Solve for x: |0.541x+7|=x^2-4

The solution is x=(541-3sqrt(4921409))/(2000)\lor x=(541+3sqrt(4921409))/(2000)

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∣ 0.541 x + 7 ∣ = x^{2} - 4

x = \frac{541 - 3 4921409}{2000} or x = \frac{541 + 3 4921409}{2000}

Decimal Notation

x = - 3.05713 \dots, x = 3.59813 \dots

Solution steps

∣ 0.541 x + 7 ∣ = x^{2} - 4

Find positive and negative intervals

x < - \frac{7000}{541}, x \geq - \frac{7000}{541}

Solve the inequality for each interval

No Solution or (x = \frac{541 - 3 4921409}{2000} or x = \frac{541 + 3 4921409}{2000})

x = \frac{541 - 3 4921409}{2000} or x = \frac{541 + 3 4921409}{2000}

∣ 8 x + 2 ∣ = - 18

5 ∣ x + 7 ∣ + 10 = 40

∣ x + 7 ∣ - 5 = 12

x^{2} - 1 - ∣ x ∣ = 0

1 = ∣ 9 + a ∣

What is the answer to |0.541x+7|=x^2-4 ?
The answer to |0.541x+7|=x^2-4 is x=(541-3sqrt(4921409))/(2000)\lor x=(541+3sqrt(4921409))/(2000)
Solve for x: |0.541x+7|=x^2-4
The solution is x=(541-3sqrt(4921409))/(2000)\lor x=(541+3sqrt(4921409))/(2000)