What are the solutions to the equation x^2-18x+90=0 ?

The solutions to the equation x^2-18x+90=0 are x=9+3i,x=9-3i

Find the zeros of x^2-18x+90=0

The zeros of x^2-18x+90=0 are x=9+3i,x=9-3i

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x^{2} - 18 x + 90 = 0

x = 9 + 3 i, x = 9 - 3 i

Solution steps

x^{2} - 18 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 90 : 6 i

x_{1, 2} = \frac{- ( - 18 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 18 ) + 6 i}{2 \cdot 1} : 9 + 3 i

x = \frac{- ( - 18 ) - 6 i}{2 \cdot 1} : 9 - 3 i

The solutions to the quadratic equation are:

x = 9 + 3 i, x = 9 - 3 i

1 6^{\frac{3}{4}}

2 x + 22 = 12

27 + 90 + x = 180

\frac{11}{4} + \frac{3}{2}

- 7 x = x^{2} + 12

What are the solutions to the equation x^2-18x+90=0 ?
The solutions to the equation x^2-18x+90=0 are x=9+3i,x=9-3i
Find the zeros of x^2-18x+90=0
The zeros of x^2-18x+90=0 are x=9+3i,x=9-3i