What are the solutions to the equation 4x^2+100x+600=0 ?

The solutions to the equation 4x^2+100x+600=0 are x=-10,x=-15

Find the zeros of 4x^2+100x+600=0

The zeros of 4x^2+100x+600=0 are x=-10,x=-15

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4 x^{2} + 100 x + 600 = 0

x = - 10, x = - 15

Solution steps

4 x^{2} + 100 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 4 \cdot 600}{2 \cdot 4}

10 0^{2} - 4 \cdot 4 \cdot 600 = 20

x_{1, 2} = \frac{- 100 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 100 + 20}{2 \cdot 4}, x_{2} = \frac{- 100 - 20}{2 \cdot 4}

x = \frac{- 100 + 20}{2 \cdot 4} : - 10

x = \frac{- 100 - 20}{2 \cdot 4} : - 15

The solutions to the quadratic equation are:

x = - 10, x = - 15

\frac{26 \cdot 25}{3.8} = x - (26 \cdot 9.8)

1^{0.5}

lo g_{4} (4096)

- 4 x \geq - 11

t - 4 = 0

What are the solutions to the equation 4x^2+100x+600=0 ?
The solutions to the equation 4x^2+100x+600=0 are x=-10,x=-15
Find the zeros of 4x^2+100x+600=0
The zeros of 4x^2+100x+600=0 are x=-10,x=-15