What are the solutions to the equation 41.1=4x^2 ?

The solutions to the equation 41.1=4x^2 are x=(sqrt(411))/(2sqrt(10)),x=-(sqrt(411))/(2sqrt(10))

Find the zeros of 41.1=4x^2

The zeros of 41.1=4x^2 are x=(sqrt(411))/(2sqrt(10)),x=-(sqrt(411))/(2sqrt(10))

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41.1 = 4 x^{2}

x = \frac{411}{2 10}, x = - \frac{411}{2 10}

Decimal Notation

x = 3.20546 \dots, x = - 3.20546 \dots

Solution steps

41.1 = 4 x^{2}

Switch sides

4 x^{2} = 41.1

Divide both sides by

4

x^{2} = 10.275

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10.275, x = - 10.275

10.275 = \frac{411}{2 10}

- 10.275 = - \frac{411}{2 10}

x = \frac{411}{2 10}, x = - \frac{411}{2 10}

2 x^{2} - 11 x - 40

7 x^{2} - x = 2 x - x^{2}

i^{4}

5 x^{2} - 4 x - 28

5 - \frac{3}{4}

What are the solutions to the equation 41.1=4x^2 ?
The solutions to the equation 41.1=4x^2 are x=(sqrt(411))/(2sqrt(10)),x=-(sqrt(411))/(2sqrt(10))
Find the zeros of 41.1=4x^2
The zeros of 41.1=4x^2 are x=(sqrt(411))/(2sqrt(10)),x=-(sqrt(411))/(2sqrt(10))