What is (x+2)/3 <(x^2)/(3x+4) ?

The solution to (x+2)/3 <(x^2)/(3x+4) is -4/3 <x<-4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+2)/3 <(x^2)/(3x+4)

\frac{x + 2}{3} < \frac{x ^{2}}{3 x + 4}

- \frac{4}{3} < x < - \frac{4}{5}

Solution steps

\frac{x + 2}{3} < \frac{x ^{2}}{3 x + 4}

Rewrite in standard form

\frac{10 x + 8}{3 x + 4} < 0

Factor

\frac{10 x + 8}{3 x + 4} : \frac{2 ( 5 x + 4 )}{3 x + 4}

\frac{2 ( 5 x + 4 )}{3 x + 4} < 0

Divide both sides by

2

\frac{\frac{2 ( 5 x + 4 )}{3 x + 4}}{2} < \frac{0}{2}

Simplify

\frac{5 x + 4}{3 x + 4} < 0

Identify the intervals

- \frac{4}{3} < x < - \frac{4}{5}

2 ab - 3 b^{2}

\frac{1}{12} \cdot 36

2 x^{2} y^{3} - 3 y^{6} z w^{9}

- 0.03 \leq x \leq 1.8

\frac{- 1}{- 9 i}

What is (x+2)/3 <(x^2)/(3x+4) ?
The solution to (x+2)/3 <(x^2)/(3x+4) is -4/3 <x<-4/5