What is the answer to |2x^2-4x+1|=1 ?

The answer to |2x^2-4x+1|=1 is x=0\lor x=1\lor x=2

Solve for x: |2x^2-4x+1|=1

The solution is x=0\lor x=1\lor x=2

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2 x^{2} - 4 x + 1 = 1

x = 0 or x = 1 or x = 2

Solution steps

2 x^{2} - 4 x + 1 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x^{2} - 4 x + 1 = - 1 or 2 x^{2} - 4 x + 1 = 1

2 x^{2} - 4 x + 1 = - 1 or 2 x^{2} - 4 x + 1 = 1

x = 1 or (x = 0 or x = 2)

x = 0 or x = 1 or x = 2

∣ - 10 x - 8 ∣ - 9 = 69

∣ 3 x - 7 ∣ - 7 = xx

∣ 2 x ∣ - 7 = 3

- 3 ∣ 3 x - 8 ∣ + 20 = 2

∣ 9 x - 17 ∣ = 1

What is the answer to |2x^2-4x+1|=1 ?
The answer to |2x^2-4x+1|=1 is x=0\lor x=1\lor x=2
Solve for x: |2x^2-4x+1|=1
The solution is x=0\lor x=1\lor x=2