What are the solutions to the equation 6x^2-11x-3=0 ?

The solutions to the equation 6x^2-11x-3=0 are x=(11+sqrt(193))/(12),x=(11-sqrt(193))/(12)

Find the zeros of 6x^2-11x-3=0

The zeros of 6x^2-11x-3=0 are x=(11+sqrt(193))/(12),x=(11-sqrt(193))/(12)

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6 x^{2} - 11 x - 3 = 0

x = \frac{11 + 193}{12}, x = \frac{11 - 193}{12}

Decimal Notation

x = 2.07437 \dots, x = - 0.24103 \dots

Solution steps

6 x^{2} - 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 (- 3) = 193

x_{1, 2} = \frac{- ( - 11 ) \pm 193}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 193}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 193}{2 \cdot 6}

x = \frac{- ( - 11 ) + 193}{2 \cdot 6} : \frac{11 + 193}{12}

x = \frac{- ( - 11 ) - 193}{2 \cdot 6} : \frac{11 - 193}{12}

The solutions to the quadratic equation are:

x = \frac{11 + 193}{12}, x = \frac{11 - 193}{12}

\frac{\frac{π}{2} - 0}{4}

2 x^{2} = - x + 6

(2 x - 1)^{2} - 2 (2 x - 1) - 3

\frac{p ^{2} + 5 p - q ^{2} + 5 q}{p - q}

∣ 2 x + 4 ∣ < 8

What are the solutions to the equation 6x^2-11x-3=0 ?
The solutions to the equation 6x^2-11x-3=0 are x=(11+sqrt(193))/(12),x=(11-sqrt(193))/(12)
Find the zeros of 6x^2-11x-3=0
The zeros of 6x^2-11x-3=0 are x=(11+sqrt(193))/(12),x=(11-sqrt(193))/(12)