What is the answer to (x-2)^2=6-|x-3| ?

The answer to (x-2)^2=6-|x-3| is x=(5-sqrt(21))/2 \lor x=(3+sqrt(29))/2

Solve for x: (x-2)^2=6-|x-3|

The solution is x=(5-sqrt(21))/2 \lor x=(3+sqrt(29))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 2)^{2} = 6 - ∣ x - 3 ∣

x = \frac{5 - 21}{2} or x = \frac{3 + 29}{2}

Solution steps

(x - 2)^{2} = 6 - ∣ x - 3 ∣

Find positive and negative intervals

x < 3, x \geq 3

Solve the inequality for each interval

x = \frac{5 - 21}{2} or x = \frac{3 + 29}{2}

1 - \frac{1}{x} - 3 = 0

10 ∣ 4 + 7 x ∣ - 6 = 94

5 ∣ x - 4 ∣ - 10 = 0

15 = 5 ∣ g ∣

∣ 2 x ∣ = x^{2} - 3 x - 6

What is the answer to (x-2)^2=6-|x-3| ?
The answer to (x-2)^2=6-|x-3| is x=(5-sqrt(21))/2 \lor x=(3+sqrt(29))/2
Solve for x: (x-2)^2=6-|x-3|
The solution is x=(5-sqrt(21))/2 \lor x=(3+sqrt(29))/2