What is the answer to 3-5|2d-3|=1 ?

The answer to 3-5|2d-3|=1 is d= 13/10 \lor d= 17/10

Solve for d: 3-5|2d-3|=1

The solution is d= 13/10 \lor d= 17/10

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3 - 5 ∣ 2 d - 3 ∣ = 1

d = \frac{13}{10} or d = \frac{17}{10}

Solution steps

3 - 5 ∣ 2 d - 3 ∣ = 1

Move

3

to the right side

- 5 ∣ 2 d - 3 ∣ = - 2

Divide both sides by

- 5

∣ 2 d - 3 ∣ = \frac{2}{5}

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 d - 3 = - \frac{2}{5} or 2 d - 3 = \frac{2}{5}

2 d - 3 = - \frac{2}{5} or 2 d - 3 = \frac{2}{5}

d = \frac{13}{10} or d = \frac{17}{10}

0.25 = ∣ a - 1.5 ∣

∣ - 8 s - 800 ∣ = 0

- 2 ∣ p ∣ - 6 = - 10

∣ 2 x - 3 ∣ - 4 = 5

0 = - 4 ∣ z + 4 ∣

What is the answer to 3-5|2d-3|=1 ?
The answer to 3-5|2d-3|=1 is d= 13/10 \lor d= 17/10
Solve for d: 3-5|2d-3|=1
The solution is d= 13/10 \lor d= 17/10