What is the answer to |x^2-12x+31|=4 ?

The answer to |x^2-12x+31|=4 is x=3\lor x=5\lor x=7\lor x=9

Solve for x: |x^2-12x+31|=4

The solution is x=3\lor x=5\lor x=7\lor x=9

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x^{2} - 12 x + 31 = 4

x = 3 or x = 5 or x = 7 or x = 9

Solution steps

x^{2} - 12 x + 31 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 12 x + 31 = - 4 or x^{2} - 12 x + 31 = 4

x^{2} - 12 x + 31 = - 4 or x^{2} - 12 x + 31 = 4

(x = 5 or x = 7) or (x = 3 or x = 9)

x = 3 or x = 5 or x = 7 or x = 9

x, f = ∣ x ∣ + 4

∣ 3 - 2 t ∣ + 1 = 10

8 - 9 ∣ 7 + 10 x ∣ = - 19

∣ 5 x + 10 ∣ - 8 = 27

∣ x + 4 ∣ = 2 x - 7

What is the answer to |x^2-12x+31|=4 ?
The answer to |x^2-12x+31|=4 is x=3\lor x=5\lor x=7\lor x=9
Solve for x: |x^2-12x+31|=4
The solution is x=3\lor x=5\lor x=7\lor x=9