What is the answer to |x^2-2x-5|=2 ?

The answer to |x^2-2x-5|=2 is x=1-2sqrt(2)\lor x=-1\lor x=3\lor x=1+2sqrt(2)

Solve for x: |x^2-2x-5|=2

The solution is x=1-2sqrt(2)\lor x=-1\lor x=3\lor x=1+2sqrt(2)

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x^{2} - 2 x - 5 = 2

x = 1 - 22 or x = - 1 or x = 3 or x = 1 + 22

Decimal Notation

x = - 1.82842 \dots, x = - 1, x = 3, x = 3.82842 \dots

Solution steps

x^{2} - 2 x - 5 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x - 5 = - 2 or x^{2} - 2 x - 5 = 2

x^{2} - 2 x - 5 = - 2 or x^{2} - 2 x - 5 = 2

(x = - 1 or x = 3) or (x = 1 - 22 or x = 1 + 22)

x = 1 - 22 or x = - 1 or x = 3 or x = 1 + 22

\frac{1}{5} ∣ x - 6 ∣ = 13

2 - 5 ∣ 3 x + 2 ∣ = - 8

∣ 7 x + 1 ∣ = - 3

∣ 2 x + 2 ∣ - 10 = 8

∣ k + 17 ∣ = 29

What is the answer to |x^2-2x-5|=2 ?
The answer to |x^2-2x-5|=2 is x=1-2sqrt(2)\lor x=-1\lor x=3\lor x=1+2sqrt(2)
Solve for x: |x^2-2x-5|=2
The solution is x=1-2sqrt(2)\lor x=-1\lor x=3\lor x=1+2sqrt(2)