What is the answer to |a+4|+4a^2-5a=8 ?

The answer to |a+4|+4a^2-5a=8 is a=(1-sqrt(5))/2 \lor a=(1+sqrt(5))/2

Solve for a: |a+4|+4a^2-5a=8

The solution is a=(1-sqrt(5))/2 \lor a=(1+sqrt(5))/2

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∣ a + 4 ∣ + 4 a^{2} - 5 a = 8

a = \frac{1 - 5}{2} or a = \frac{1 + 5}{2}

Decimal Notation

a = - 0.61803 \dots, a = 1.61803 \dots

Solution steps

∣ a + 4 ∣ + 4 a^{2} - 5 a = 8

Find positive and negative intervals

a < - 4, a \geq - 4

Solve the inequality for each interval

No Solution or (a = \frac{1 - 5}{2} or a = \frac{1 + 5}{2})

a = \frac{1 - 5}{2} or a = \frac{1 + 5}{2}

∣ - 4 x - 3 ∣ = 17

4 ∣ v - 2 ∣ - 3 = - 25

∣ u + 4 ∣ = 2 ∣

∣ t - 1 ∣ - 7 = - 18

∣ 2 x + 4 ∣ = x - 3

What is the answer to |a+4|+4a^2-5a=8 ?
The answer to |a+4|+4a^2-5a=8 is a=(1-sqrt(5))/2 \lor a=(1+sqrt(5))/2
Solve for a: |a+4|+4a^2-5a=8
The solution is a=(1-sqrt(5))/2 \lor a=(1+sqrt(5))/2