What is the answer to |x^2+4x-1|=4 ?

The answer to |x^2+4x-1|=4 is x=-5\lor x=-3\lor x=-1\lor x=1

Solve for x: |x^2+4x-1|=4

The solution is x=-5\lor x=-3\lor x=-1\lor x=1

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x^{2} + 4 x - 1 = 4

x = - 5 or x = - 3 or x = - 1 or x = 1

Solution steps

x^{2} + 4 x - 1 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 4 x - 1 = - 4 or x^{2} + 4 x - 1 = 4

x^{2} + 4 x - 1 = - 4 or x^{2} + 4 x - 1 = 4

(x = - 3 or x = - 1) or (x = - 5 or x = 1)

x = - 5 or x = - 3 or x = - 1 or x = 1

∣ - 3 b ∣ = 3

∣ 3 y + 6 ∣ = 3

∣ 3 y + 6 ∣ = 2

∣ 5 x + 3 ∣ + (- 2) x + 7 = 21

195 - 3 \cdot ∣ - x ∣ = 27

What is the answer to |x^2+4x-1|=4 ?
The answer to |x^2+4x-1|=4 is x=-5\lor x=-3\lor x=-1\lor x=1
Solve for x: |x^2+4x-1|=4
The solution is x=-5\lor x=-3\lor x=-1\lor x=1