What are the solutions to the equation -1/4 x^2+x+1=0 ?

The solutions to the equation -1/4 x^2+x+1=0 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))

Find the zeros of -1/4 x^2+x+1=0

The zeros of -1/4 x^2+x+1=0 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))

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- \frac{1}{4} x^{2} + x + 1 = 0

x = - 2 (2 - 1), x = 2 (1 + 2)

Solution steps

- \frac{1}{4} x^{2} + x + 1 = 0

Multiply both sides by

4

- x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 4 = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4 2}{2 ( - 1 )}

x = \frac{- 4 + 4 2}{2 ( - 1 )} : - 2 (2 - 1)

x = \frac{- 4 - 4 2}{2 ( - 1 )} : 2 (1 + 2)

The solutions to the quadratic equation are:

x = - 2 (2 - 1), x = 2 (1 + 2)

∣ 3 z - 9 ∣ > ∣ 3 z - 4 ∣

12 x^{4} y z^{2} - 8 x^{3} y^{3} z^{2}

\frac{9 !}{2 ! 2 !}

x + 8 = 4 x + 20

3.2 = \frac{4}{5} (b - 5)

What are the solutions to the equation -1/4 x^2+x+1=0 ?
The solutions to the equation -1/4 x^2+x+1=0 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))
Find the zeros of -1/4 x^2+x+1=0
The zeros of -1/4 x^2+x+1=0 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))