What is the answer to 3|x^2+x-2|=0 ?

The answer to 3|x^2+x-2|=0 is x=-2\lor x=1

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3|x^2+x-2|=0

3 x^{2} + x - 2 = 0

x = - 2 or x = 1

Solution steps

3 x^{2} + x - 2 = 0

Divide both sides by

3

x^{2} + x - 2 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x^{2} + x - 2 = 0

x^{2} + x - 2 = 0 : x = 1, x = - 2

x = - 2 or x = 1

4 ∣ 3 x - 6 ∣ + 6 = 2

∣ x - 7 + 6 x ∣ - 6 = 22

4 - 6 ∣ 8 x - 4 ∣ = 58

∣ α + (α - 1) + (α + 1) ∣ = 2

4 ∣ 3 x - 6 ∣ + 3 = 15